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X^2+6X-35.5=0
a = 1; b = 6; c = -35.5;
Δ = b2-4ac
Δ = 62-4·1·(-35.5)
Δ = 178
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{178}}{2*1}=\frac{-6-\sqrt{178}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{178}}{2*1}=\frac{-6+\sqrt{178}}{2} $
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